#!/bin/bash
# bad-op.sh: Trying to use a string comparison on integers.
echo
number=1
# The following "while loop" has two errors:
#+ one blatant, and the other subtle.
while [ "$number" < 5 ] # Wrong! Should be: while [ "$number" -lt 5 ]
do
echo -n "$number "
let "number += 1"
done
# Attempt to run this bombs with the error message:
#+ bad-op.sh: line 10: 5: No such file or directory
# Within single brackets, "<" must be escaped,
#+ and even then, it's still wrong for comparing integers.
echo "---------------------"
while [ "$number" \< 5 ] # 1 2 3 4
do #
echo -n "$number " # This *seems to work, but . . .
let "number += 1" #+ it actually does an ASCII comparison,
done #+ rather than a numerical one.
echo; echo "---------------------"
# This can cause problems. For example:
lesser=5
greater=105
if [ "$greater" \< "$lesser" ]
then
echo "$greater is less than $lesser"
fi # 105 is less than 5
# In fact, "105" actually is less than "5"
#+ in a string comparison (ASCII sort order).
echo
exit 0
