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PHP Website Status Online Check

Website Status Online Check

<?
function online($link) {
  if (isset($link) && $link != "") {

    $part = explode(":",$link);

    if (empty($part[1])) { $part[1] = 80; }

      $churl = @fsockopen($link, $part[1], $errno, $errstr, 20);
      if (!$churl) { echo "ON http://$link (Offline)<BR>"; }
      else { echo "OFF http://$link (Online)<BR>"; }
   }
}
online("google.com");
?>